QStackedWidget Class
The QStackedWidget class provides a stack of widgets where only one widget is visible at a time. 更多...
| 头文件: | #include <QStackedWidget> |
| qmake: | QT += widgets |
| 基类: | QFrame |
属性
- count : const int
- currentIndex : int
公有函数
| QStackedWidget(QWidget *parent = Q_NULLPTR) | |
| ~QStackedWidget() | |
| int | addWidget(QWidget *widget) |
| int | count() const |
| int | currentIndex() const |
| QWidget * | currentWidget() const |
| int | indexOf(QWidget *widget) const |
| int | insertWidget(int index, QWidget *widget) |
| void | removeWidget(QWidget *widget) |
| QWidget * | widget(int index) const |
- 14 个公有函数继承自 QFrame
- 214 个公有函数继承自 QWidget
- 32 个公有函数继承自 QObject
- 14 个公有函数继承自 QPaintDevice
公有槽函数
| void | setCurrentIndex(int index) |
| void | setCurrentWidget(QWidget *widget) |
信号
| void | currentChanged(int index) |
| void | widgetRemoved(int index) |
重新实现的受保护函数
| virtual bool | event(QEvent *e) |
- 4 个受保护的函数继承自 QFrame
- 35 个受保护的函数继承自 QWidget
- 9 个受保护的函数继承自 QObject
- 1 个受保护的函数继承自 QPaintDevice
其他继承的成员
- 1 个公有变量继承自 QObject
- 5 个静态公有成员继承自 QWidget
- 10 个静态公有成员继承自 QObject
- 4 个受保护的函数继承自 QFrame
- 35 个受保护的函数继承自 QWidget
- 9 个受保护的函数继承自 QObject
- 1 个受保护的函数继承自 QPaintDevice
- 1 个受保护的槽函数继承自 QWidget
- 2 个受保护的变量继承自 QObject
- 1 protected type inherited from QPaintDevice
详细描述
The QStackedWidget class provides a stack of widgets where only one widget is visible at a time.
QStackedWidget can be used to create a user interface similar to the one provided by QTabWidget. It is a convenience layout widget built on top of the QStackedLayout class.
Like QStackedLayout, QStackedWidget can be constructed and populated with a number of child widgets ("pages"):
QWidget *firstPageWidget = new QWidget;
QWidget *secondPageWidget = new QWidget;
QWidget *thirdPageWidget = new QWidget;
QStackedWidget *stackedWidget = new QStackedWidget;
stackedWidget->addWidget(firstPageWidget);
stackedWidget->addWidget(secondPageWidget);
stackedWidget->addWidget(thirdPageWidget);
QVBoxLayout *layout = new QVBoxLayout;
layout->addWidget(stackedWidget);
setLayout(layout);
QStackedWidget provides no intrinsic means for the user to switch page. This is typically done through a QComboBox or a QListWidget that stores the titles of the QStackedWidget's pages. For example:
QComboBox *pageComboBox = new QComboBox;
pageComboBox->addItem(tr("Page 1"));
pageComboBox->addItem(tr("Page 2"));
pageComboBox->addItem(tr("Page 3"));
connect(pageComboBox, SIGNAL(activated(int)),
stackedWidget, SLOT(setCurrentIndex(int)));
When populating a stacked widget, the widgets are added to an internal list. The indexOf() function returns the index of a widget in that list. The widgets can either be added to the end of the list using the addWidget() function, or inserted at a given index using the insertWidget() function. The removeWidget() function removes a widget from the stacked widget. The number of widgets contained in the stacked widget can be obtained using the count() function.
The widget() function returns the widget at a given index position. The index of the widget that is shown on screen is given by currentIndex() and can be changed using setCurrentIndex(). In a similar manner, the currently shown widget can be retrieved using the currentWidget() function, and altered using the setCurrentWidget() function.
Whenever the current widget in the stacked widget changes or a widget is removed from the stacked widget, the currentChanged() and widgetRemoved() signals are emitted respectively.
参见 QStackedLayout, QTabWidget, and Config Dialog Example.
属性
count : const int
This property holds the number of widgets contained by this stacked widget
By default, this property contains a value of 0.
访问函数:
| int | count() const |
参见 currentIndex() and widget().
currentIndex : int
This property holds the index position of the widget that is visible
The current index is -1 if there is no current widget.
By default, this property contains a value of -1 because the stack is initially empty.
访问函数:
| int | currentIndex() const |
| void | setCurrentIndex(int index) |
Notifier signal:
| void | currentChanged(int index) |
参见 currentWidget() and indexOf().
成员函数
QStackedWidget::QStackedWidget(QWidget *parent = Q_NULLPTR)
Constructs a QStackedWidget with the given parent.
参见 addWidget() and insertWidget().
QStackedWidget::~QStackedWidget()
Destroys this stacked widget, and frees any allocated resources.
int QStackedWidget::addWidget(QWidget *widget)
Appends the given widget to the QStackedWidget and returns the index position. Ownership of widget is passed on to the QStackedWidget.
If the QStackedWidget is empty before this function is called, widget becomes the current widget.
参见 insertWidget(), removeWidget(), and setCurrentWidget().
[signal] void QStackedWidget::currentChanged(int index)
This signal is emitted whenever the current widget changes.
The parameter holds the index of the new current widget, or -1 if there isn't a new one (for example, if there are no widgets in the QStackedWidget).
Note: Notifier signal for property currentIndex.
参见 currentWidget() and setCurrentWidget().
QWidget *QStackedWidget::currentWidget() const
Returns the current widget, or 0 if there are no child widgets.
参见 currentIndex() and setCurrentWidget().
[virtual protected] bool QStackedWidget::event(QEvent *e)
重新实现 QObject::event().
int QStackedWidget::indexOf(QWidget *widget) const
Returns the index of the given widget, or -1 if the given widget is not a child of the QStackedWidget.
参见 currentIndex() and widget().
int QStackedWidget::insertWidget(int index, QWidget *widget)
Inserts the given widget at the given index in the QStackedWidget. Ownership of widget is passed on to the QStackedWidget. If index is out of range, the widget is appended (in which case it is the actual index of the widget that is returned).
If the QStackedWidget was empty before this function is called, the given widget becomes the current widget.
Inserting a new widget at an index less than or equal to the current index will increment the current index, but keep the current widget.
参见 addWidget(), removeWidget(), and setCurrentWidget().
void QStackedWidget::removeWidget(QWidget *widget)
Removes widget from the QStackedWidget. i.e., widget is not deleted but simply removed from the stacked layout, causing it to be hidden.
Note: Parent object and parent widget of widget will remain the QStackedWidget. If the application wants to reuse the removed widget, then it is recommended to re-parent it.
参见 addWidget(), insertWidget(), and currentWidget().
[slot] void QStackedWidget::setCurrentWidget(QWidget *widget)
Sets the current widget to be the specified widget. The new current widget must already be contained in this stacked widget.
参见 currentWidget() and setCurrentIndex().
QWidget *QStackedWidget::widget(int index) const
Returns the widget at the given index, or 0 if there is no such widget.
参见 currentWidget() and indexOf().
[signal] void QStackedWidget::widgetRemoved(int index)
This signal is emitted whenever a widget is removed. The widget's index is passed as parameter.
参见 removeWidget().